V Omega Cross R

The angular velocity is positive since the satellite travels eastward with the earth s rotation counter clockwise from above the north pole.

V omega cross r. Tangential velocity v is equal to the angular velocity omega times the radius r. To be consistent with the vector notation when r points to the center of mass from the center of rotation it is v omega r in scalar form and vec v vec omega times vec r in vector form where times is the vector cross product. Likewise at the final position theta 1 and t1 the angular velocity changes to an angular velocity omega 1. Start date jan 30 2013.

In physics circular motion is a movement of an object along the circumference of a circle or rotation along a circular path. Jan 30 2013 1 hi problem 1. To see this let s first check its direction and then its magnitude. Curl v omega cross r.

So the direction is correct. Since and are mutually orthogonal the angle between them is so that by eq. For angular displacement phi v omega r ra rb va vb when we initially specify the rotation of our object with theta 0 and t0 we should also specify an initial instantaneous angular velocity omega 0. What i want to do in this video is a calculus proof of the famous centripetal acceleration formula that tells us the magnitude of centripetal acceleration the actual direction will change it s always going to be pointing inwards but the magnitude of centripetal acceleration is equal to the magnitude of the velocity squared divided by the radius i want to be very clear this is a scalar.

The rotation around a fixed axis of a three dimensional body involves circular motion of its parts. By the right hand rule points up out of the page in fig b 4 crossing that with again by the right hand rule produces a tangential velocity vector pointing as shown in the figure. Status not open for further replies. The equations of motion describe the.

With orbital radius 42 000 km from the earth s center the satellite s speed through space is thus v 42 000 km 0 26 h 11 000 km h.